Question

Se considera ∆dreptunghic ABC ,m(<A)=90°. Daca AB=6cm ,BC=10cm ,calculati AC,sin C ,cos C ,tgB,ctgB

Answer 1

T.Pitagora si avem AC patrat= BC patrat- AB patrat
AC = radical din 64 = 8
sin C = AB / BC
sin C = 6 / 10 = 0,6
cos C = AC / BC
cos C = 8 / 10 = 0,8
tg B = AC /AB = 8 / 6 = 4/3
ctg B = AB / AC = 6 / 8= 3/4