Question

Se consideră expresia E(x)=(3x-1)-7(x+1)(x-2)-(x+3)^2 , unde x este numar real.Aratati ca E(0)×E(1)×E(2)×.....×E(2020)=0.

Va rog ajutati-ma la acest exercițiu!!!​

Answer 1

Răspuns:

E(0)×E(1)×0×.....×E(2020)=0

Explicație pas cu pas:

E(x)=(3x-1)²-7(x+1)(x-2)-(x+3)², unde x este numar real.

E(x)=9x²-6x+1-7(x²-x-2)-(x²+6x+9)

E(x)=9x²-6x+1-7x²+7x+14-x²-6x-9

E(x)= x²-5x+6

E(x)=x²-2x-3x+6

E(x)=x(x-2)-3(x-2)

E(x)=(x-2)(x-3)

E(2)=E(3)=0

=> E(0)×E(1)×0×.....×E(2020)=0