Question

se considera expresia E(x)=4/x-2÷(x+3)^2-(x+1)^2/x^2-4​

Answer 1

$e(x)=\frac{4}{x-2}:\frac{(x+3)^2-(x+1)^2}{x^2-4}$

//$(x+3)^{2}=x^{2} +6x+9$

//$(x+1)^{2} =x^{2} +2x+1$

$\frac{4}{x-2} *\frac{(x-2)(x+2)}{x^{2} +6x+9-x^{2} -2x-1}$

$\frac{4(x+2)}{4x+8} =\frac{4(x+2)}{4(x+2)} =\frac{4}{4} =1$