Question

se considera expresia E(x)=x/x^2+3x -(1/x-3 -1/x+3)÷6/x-3​

Answer 1

$e(x)=\frac{x}{x^2+3x} -(\frac{1}{x-3} -\frac{1}{x+3} ):\frac{6}{x-3}$

$\frac{x}{x(x+3)}-\frac{x+3-x+3}{(x-3)(x+3)}*\frac{x-3}{6}$

$\frac{1}{x+3}-\frac{6}{x+3} *\frac{1}{6}$

$\frac{1}{x+3}-\frac{1}{x+3}=0$