Question

se considera f:R ->R f(x) f(x) = x2+5 arati ca f(x) -f (-x) =0 pentru orce numar real x​

Answer 1

$f : \mathbb{R} \rightarrow \mathbb{R}, f(x) = x^{2} + 5$

$f(-x) = (-x)^{2} + 5 = x^{2} + 5 = f(x) \implies f(x) - f(-x) = 0$