Question

Se considera functia f:F->R , f(x)=ax+b . Determinati nr reale a si b stiind ca f(0)=1 si f(x+1)=f(x)+2

Answer 1

f (0)=a×0+b=1 at b=1
f (x+1)=a (x+1)+b=ax+b+2
ax+a+1=ax+1+2
a=3-1
a=2