Question

Se considera functia f:R->R
f(x)=ax+b , unde a si b sunt nr. reale ptr care f(-1)=-5 si f(0)=-2
Aratati ca f(1)=1

Answer 1

[tex]f(-1)=-5 => - a+b = -5 \\ f(0)=-2 => b=-2\\ (-a+b) - b = -5 - (-2) => -a = -3 => a=3 \\ =>f(x)=3x-2 \\ =>f(1) = 3 * 1 - 2 = 3 -2 = 1[/tex]