Question

se considera functia fx)x la patrat +2x-4 . coordonate varfului parabolei

Answer 1

Răspuns:

f(x)=x²+2x-4

Varful are coordonate V(-b/2a,-Δ/4a)

-b/2a=-2/2*1=-2/2= -1

Δ=b²-4ac

Δ=2²-4*1*(-4)=4+16=20

-Δ/4a= -20/4*1= -20/4 = -5

V(-1, -5)

Explicație pas cu pas:

Answer 2

varful unei parabole are coordonatele (-b/2a; -delta/4a)

fx=x^2+2x-4

a=1

b=2

c=-4

calculam delta=b^2-4ac

delta=4+16

delta=20

deci V:(-2/2; -20/4)

V:(-1;-5)