Question

Se considera mulțimea A={-4;-2;6;2/5;radical din5;3,(25),radical din 5.(4),6x2 pe 7,radical din 45}
A reunit cu N, A reunit cu Z, A reunit cu Q, A reunit (Z-N), A reunit cu (R-Q), A/Q

Answer 1

3,(25)=(325-3)/99=323/99
√5,(4)=√(54-5)/9=√51/9=√51/√9=√51/3
6 intreg1/7=(6·7+1)/7=43/7
A={-4; -2; 6; 3 ; 2/5, √5; 323/99; √51/3; 43/7; √45}
AintersectatN={3,6}
Aintersectat Z={-4; -2; 3; 6}
Aintersectat Q={2/5; 323/99; 43/7}
Ainterctat (Z-N)={-4, -2}
Aintersectat (R-Q)={√5; √51/3; √45}
A\Q={-4,-2,3,6, √5, √51/3, √45}