Question

se considera nr a=(1,1^2+1,2^2-1,3^2):4+6:10^2si b=(26:2,6-1,8:0,3):(21,19-0,3-0,89) calculati a^2+2ab+b^2

A) Calculati a si b
B) Calculati a^2+b^2 si a^2-b^2
C) Calculati (a+b)^2 si a^2+2ab+b^2
D) Calculati (a-b)^2 si a^2-2ab+b^2

Answer 1

$A)a = ( {1.1}^{2} + {1.2}^{2} - {1.3}^{2} ) \div 4 + 6 \div {10}^{2}$

$a = (1.21 + 1.44 - 1.69) \div 4 + 6 \div 100$

$a = 0.96 \div 4 + 0.06$

$a = 0.24 + 0.06$

$a = 0.3$

$b = (26 \div 2.6 - 1.8 \div 0.3) \div (21.19 - 0.3 - 0.89)$

$b = (10 - 6) \div 20$

$b = 4 \div 20$

$b = 0.2$

$B) {a}^{2} + {b}^{2} = {0.3}^{2} + {0.2}^{2} = 0.09 + 0.04 = 0.13$

${a}^{2} - {b}^{2} = {0.3}^{2} - {0.2}^{2} = 0.09 - 0.04 = 0.05$

$C) {(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} = {0.3}^{2} + 2 \times 0.3 \times 0.2 + {0.2}^{2} = 0.09 + 0.12 + 0.04 = 0.25$

$D) {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} = {0.3}^{2} - 2 \times 0.3 \times 0.2 + {0.2}^{2} = 0.09 - 0.12 + 0.04 = 0.01$