Question

Se considera nr a = 9supra8+35supra40-27supra72+7supra8 . scrieti nr a sub forma de fractie ordinala ireductibila

Answer 1

a=9/8 +35/40 - 27/72 +7/8= 9/8 + 7/8 (am simplif cu 5) -3/8 (simplif cu 9)+ 7/8= =20/8=5/2 (am simplif cu 4)
deci a=5/2

Answer 2

9/8+35/40-27/72+7/8=
=9/8+7/8-3/8+7/8
=(9+7-3+7)/8
=20/8
=5/2