Question

Se considera nr a,b,c,d direct proportionale cu 5,4,2,3.stiind ca bc=4d,determinati multimea divizorilor nr a+b+c+d

Answer 1

a/5=b/4=c/2=d/3=k
a=5k, b=4k, c=2k, d=3k
bc=4d inlocuiesc si am
4k*2k=4*3k
impart prin k
8k=12
k=12/8=3/2
a=5*3/2=15/2
b=12/2=6
c=6/2=3
d=9/2
a+b+c+d=15/2+6+3+9/2=24/2+9=12+9=21
D 21∈ {1,3,7,21}