Question

se considera nr a=log5din2 .Arătați ca log5din10=1+a
helppp

Answer 1

$a = log_{5}(2)$

$log_{5}(10) = 1 + a$

$1 = log_{5}(5)$

$log_{5}(10) = log_{5}(5) + log_{5}(2)$

$log_{5}(10) = log_{5}(5 \times 2)$

$log_{5}(10) = log_{5}(10) \: \: (A)$

Answer 2

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