Question

Se considera numerele a=1/2+2/3+3/4+4/5+5/6+6/7 si b=1/2+1/3+1/4+1/5+1/6+1/7.Calculati ca a +2004+b este un numar natural (DAU COROANA) ​

Answer 1

Răspuns:

Explicație pas cu pas:

a + b = 1/2+2/3+3/4+4/5+5/6+6/7+1/2+1/3+1/4+1/5+1/6+1/7

= (1/2 + 1/2) + (2/3 + 1/3) + (3/4 + 1/4) + (4/5 + 1/5) + (5/6 + 1/6) + (6/7 + 1/7)

= 2/2 + 3/3 + 4/4 + 5/5 + 6/6 + 7/7

= 1 + 1 + 1 + 1 + 1 + 1 = 6

a + 2004 + b = 6 + 2004 = 2010 = numar natural (adica intreg si pozitiv)