Question

se considera numerele a =[(2^3)^5:(2^6)^2+2^11:(7×2^5+2^5)]×(2^5)^13
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Answer 1

Răspuns:

Explicație pas cu pas:

a = [ ( 2³)⁵ : (2⁶)² + 2¹¹ : ( 7 x 2⁵ + 2⁵ )] x (2⁵ )¹³

a = { 2³ˣ⁵ : 2⁶ˣ² + 2¹¹ : [2⁵ x ( 7 + 1) ] }x 2⁵ˣ¹³

a = [ 2¹⁵⁻¹² + 2¹¹ : (2⁵x 8) ] x 2⁶⁵

a = [ 2³ + 2¹¹ : (2⁵ x 2³ )] x 2⁶⁵

a = ( 8 + 2¹¹ : 2⁸ ) x 2⁶⁵

a = (8 + 2¹¹⁻⁸ ) x 2⁶⁵

a = ( 8 + 2³) x 2⁶⁵

a = 16 x 2⁶⁵

a = 2⁴⁺⁶⁵

a = 2⁶⁹