Question

se considera numerele a=(4·7-3·8+2):2
b=11-[17-(3^2-2^3+2·4)]
c={[8·10^2+7·10^2·(6·10^2-5·10^2)]:50-1416}^100
Calculati:a^b+b^c+c^a.

(OFER CORONITA)

Answer 1

$a = (4*7 - 3*8 + 2):2 = (28-24+2):2 = (4+2):2 = 6:2=3 \\ b = 11-[17-(3^{2} - 2^{3} + 2*4)] = 11-[ 17- (9 - 8 + 8)] = 11-[17-9] = 11-8= 3 \\ c= [[(8*10^{2}+7*10^{2}*(6*10^{2}-5*10^{2})]:50-1416]^{100} = [[800+700*(600-500)]:50-1416]^{100} = [[800+700*100]:50-1416]^{100} = [70800:50-1416]^{100} = [ 1416 - 1416]^{100} = 0^{100} = 0. \\ a^{b}+b^{c} +c^{a} = 3^{3} + 3^{0} + 0^{3} = 27 + 1 + 0 = 28$