Question

Se considera numerele a=(5^30+ 5^29+ 5^28): 5^28−3^3 si b=√144/36+√7−√9 +

|−3√3−√25|−√27..5pa)Demonstrati ca a= 4b)Calculati media geometrica a numerelor a si b DAU COROANA!

Answer 1

Răspuns:

Explicație pas cu pas:

a=(5³⁰+5²⁹+5²⁸):5²⁸-3³=5²⁸(5³⁰⁻²⁸+5²⁹⁻²⁸+5²⁸⁻²⁸):5²⁸-3³=5²⁸(5²+5¹+5⁰):5²⁸-3³=5²⁸(25+5+1)-3³=31-3³=31-27=4

a=4

b=√144/36+√7-√9+I-3√3-√25I-√27=√12²/6²+√7-√3²+I-3√3-√5²I-3√3=12/6+√7+I-3√3-5I=2+√7+3√3+5-3√3=7+√7

b=7+√7

mg=√axb=√4(7+√7)=2√7+√7