Question

se considera numerele a= ($\sqrt{27}$ +2$\sqrt{12}$ - $\frac{6}{\sqrt{3} }$ * $\frac{5}{\sqrt{3} }$) si b =$(0,(3))^{-1}$.


aflati $(8b-a)^{101}$

Answer 1

a)3V3+4V3-30/3=7V3-10
b)(0,(3))^-1=(3/9)^-1=(1/3)^-1=3
(8b-a)^101=(8*3-7V3-10)^101=(24-7V3-10)^101=
(14-7V3)^101.