Question

Se considera numerele intregi: a=4, b=+3, c=-11.Calculati:
a)[(a-b)+c]+(a+c)
b)[(a-b)+(c-a)]+(b-c)
c)[(a+b)+c]+[(a-b)+c]
d)[(c-a)-b]-a

Answer 1

[(4-3)-11]+(4-11)=-10-7=-17
[(4-3)+(-11-4)]+(3+11)=(1-15)+14=-14+14=0

(7-11)-10=-14

[(-11-4)-3]-4=(-15-3)-4=-18-4=-22