Question

Se considera numerele rationale a si b,pentru care 6a/5b=0,48
a)Cat la suta reprezinta numarul a din numarul b?
b)Aflati valoarea raportului 11a-2b/9a+6b
c)Daca,in plus, 3a+2b=16,atunci determinati numerele a si b.

Answer 1

a)  6a/5b=48/100
6a/5b=12/25  ⇒ a= 5b*12/25*6
a=5b*2/25  ⇒ a= 10b/25  ⇒ a=40b/100
a= 40/100*b
a=40% *b

b) a/b=40/100=2/5 =k
a=2k si b=5k
11*2k - 2*5k / 9*2k+6*5k= 22k-10k/18k+30k= 12k/48k=12/48=1/4

c) 3*2k+ 2*5k=16
6k+10k=16
16k=16
k=16:16
k=1
a=2 si b=5