Question

se consideră numerele reale

x=>
$( \frac{8}{ \sqrt{18} } + \frac{6}{ \sqrt{2} } ) \times \frac{ \sqrt{2} }{13}$
y=>
$( \frac{5}{ \sqrt{147} } - \frac{1}{ \sqrt{3} } ) \div \frac{ \sqrt{3} }{14}$
arată ca x =>
$\frac{2}{3}$
arată ca numărul N=|y-x| este natural
​

Answer 1

Răspuns:

x=(8/√18+6/√2)×√2/13

x=(8√18/18+6√2/2)×√2/13

x=(8×3√2+9×6√2)/18 × √2/13

x=(24√2+54√2)/18 × √2/13

x=78√2/18 × √2/13

x=78/13 × √2×√2/18

x=6 × √4/18

x=2/3

y=(5/√147-1/√3) ; √3/14

y=(5√147/147-√3/3) × 14/√3

y=(5√147-49√3)/147 × 14√3/3

y=(5×7√3-49√3)/21 × 2√3/3

y=(35√3-49√3)/21 × 2√3/3

y=-14√3/21 × 2√3/3

y=-2√3/3 × 2√3/3

y=-4×3 / 9

y=-4/3

N=|y-x|

N=|-4/3-2/3|

N=|-6/3|

N=|-2|

N=2 ∈ ℕ