Question

se considera prisma triunghiulara regulata abca'b'c' reprezentata in figura alaturata. Punctul M este mijlocul muchei [BC]. Se stie ca AB=6 cm si AA`=3 cm. a) Determinati m((ABB`);(BCC`))
b) Calculati d(A;BC)
c) Determinati m((A`BC);(ABC))

Answer 1

m((ABB`);(BCC`))=m(AB,BC)=m(ABC)=60grade(triunghi echilateral)
d(A;BC)=AM=ABrad3/2=>AM=3rad3
m((A`BC);(ABC))=m(A'M,AM)=m(A'MA)=30grade
A'M=pitagora in A'MC =6
sinA'MA=AA'/A'M=3/6=1/2=>m(A'MA)=30grade