Question

se considera progresia geometrica (bn)n≥1,oricare ar fi n∈N,in care b1=3 si b2=6 .sa se calculeze b6.

Answer 1

b1=3
b2=b1·q
q=b2:b1
q=6:3
q=2
b6=b1·$q^{5}$
b6=3·$2^{5}$
b6=3·32
b6=96