Question

se considera punctele a 2, 2 b 4,0 si c 2,-2 . perimetrul triunghiului abc este

Answer 1

AB=√(xB-xA)²+(yB-yA)²

AB=√(4-2)²+(0-2)²

AB=√2²+(-2)²

AB=√4+4

AB=√8

AB=2√2

AC=√(xC-xA)²+(yC-yA)²

AC=√(2-2)²+(-2-2)²

AC=√0²+(-4)²

AC=√16

AC=4

BC=√(xC-xB)²+(yC-yB)²

BC=√(2-4)²+(-2-0)²

BC=√(-2)²+(-2)²

BC=√4+4

BC=√8

BC=2√2

PΔABC=AB+BC+AC

PΔABC=2√2+2√2+4

PΔABC=4√2+4