Question

Se considera sirul de rapoarte egale: x supra a = y supra b = z supra c = 2. Calculati

a) 2² - x+y+z supra a+b+c;


b) 2^4 - x²+y²+z² supra a²+b²+c²

Va rog repede

Answer 1

$\frac{x}{a}=\frac{y}{b}=\frac{z}{c}=2$

$\frac{x}{a}=\frac{y}{b}=\frac{z}{c}=\frac{x+y+z}{a+b+c}$

Din cele doua rezulta ca:

$\frac{x+y+z}{a+b+c} =2$

$2^2-\frac{x+y+z}{a+b+c} =4-2=2$

x=2a

y=2b

z=2c

$2^4-\frac{x^2+y^2+z^2}{a^2+b^2+c^2} =16-\frac{4a^2+4b^2+4c^2}{a^2+b^2+c^2} =16-\frac{4(a^2+b^2+c^2)}{a^2+b^2+c^2}=16-4=12$

Alta rezolvare gasesti aici: https://brainly.ro/tema/8888980

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