Question

Se considera substanța:FeO; Să se precizeze : 1)Calculul masei molare. 2)Raportul atomic 3)Raportul de masă 4)Compozitia procentuală 5)Cați moli de substanta sunt inn 80g substanta,considerata?Cate molecule se gasesc in aceasta cantitate stiind Na=6,023*10 la puterea 23?

Answer 1

Fe O oxid feros
 M=56+16=72-------> 1mol=72g
r.a.=1Fe :1 O=1:1
r.m.=AFe:AO=56:16=7:2  ( s- a simplificat cu 8 )
comp. procentuala prin masa moleculara
72g Feo---------56g Fe--------16g O
100g -------------xg-----------------yh
x=100.56:72=77,77 la suta Fe
y=100.16:72=22,22 la suta O


5.
80g FeO            1mol FeO-----------72g FeO
moli FeO            X moli----------------80g
                          x=80: 72=1,1 moli FeO
                                                                          23
                          1mol FeO-----------------6,023.10 molecule FeO
                          1,1 moli FeO-------------Y
                                                 23
                        Y=1,1. 6,023.10     molecule