Question

se considera trei nr rationale x,y,z astfel incat x/2 =y/3=z/5
a ) Cat la suta reprezinta nr cel mai mic din suma celorlalte doua?
b) Sa se afle cele tri nr stiind ca x/2+y/3+z/5 = 6/7

Answer 1

Răspuns:

Explicație pas cu pas:

x/2 = y/3 = z/5 = k

x = 2k

y = 3k

z = 5k

x/(y + z) = 2k/(3k + 5k) = 2k/8k = 2/8 = 1/4 = 25/100

x = 25%(y + z)

_____________

x/2 + y/3 + z/5 = 6/7

2k/2 + 3k/3 + 5k/5 = 6/7

k + k + k = 6/7

3k = 6/7

k = 6/7 : 3 = 6/21 = 2/7

x/2 = 2/7

x = 4/7

y/3 = 2/7

y = 6/7

z/5 = 2/7

z = 10/7