Question

se considera triunghiul dreptunghic abc,m A= 90de grade . daca BC = 25 cm , sinC = 3/5 , calculati AB , AC , cos B , tgC.

Answer 1

sin C=AB/BC
3/5=AB/25
AB=15
AC=√BC²-AB²
AC=20
cos B=AB/BC
cos B=15/25
cos B=3/5
tg C=AB/AC
tg C=15/20
tg C=3/4

Answer 2

sin(C)=3/5=AB/BC=AB/25

AB=15

AC=√(BC^2 - AB^2) = √(25^2 - 15^2) = 20

cos(B) = AC/BC=20/15=4/3

tg(C)=AB/AC=15/20=3/4