Question

Se conzidera numerele reale.Calculati:
a)a^6:a^3+a×a^2+a^3=
b)2b×b^3-b×b×b^2+5b^5:b=
c)(x^2)^3:x^3+x×x×x-2x×x^2=
d)y^3×y^5+3y×y^10:y^3-4y^15:y^7=
e)(a^3)^5:(a^2)^6+3a-(2a)^2:a=
f)b^16:(-b)^14+4b×(-b)+(-2b)^2=
Dau Coroana♡

Answer 1

$a).a^6:a^3+a*a^2+a^3=a^6^-^3+a^1^+^2+a^3=a^3+a^3+a^3=3a^3 \\ b).2b*b^3-b*b*b^2+5b^5:b=2b^4-b^4+5b^4=b^4+5b^4=6b^4 \\ c).(x^2)^3:x^3+x*x*x-2x*x^2=x^6:x^3+x^3-2x^3= \\ =x^6^-^3+x^3-2x^3=x^3+x^3-2x^3=2x^3-2x^3=0 \\ d).y^3*y^5+3y*y^1^0:y^3-4y^1^5:y^7= y^8+3y*y^7-4y^8= \\ =y^8+3y^8-4y^8=4y^8-4y^8=0$
$e).(a^3)^5:(a^2)^6+3a-(2a)^2:a=a^1^5:a^1^2+3a-4a^2:a= \\ =a^3+3a-4a=a^3-a \\ f).b^1^6:(-b)^1^4+4b*(-b)+(-2b)^2=b^2-4b^2+4b^2=b^2$