Question

se da 100kg de sodiu de p=80%. calculati nr de moli masa si volumul de hidrogen degajat in apa

Answer 1

p=m pur/m impur*100 => mpur=80*100/100= 80kg Na

2Na + 2H2O => 2NaOH + H2

2*23kg Na.........................1 kmol H2
80kg Na...........................x=1,739 kmoli H2

n=m/M=>m=n*M=1,739*2=3,47826 kg H2

n=V/Vm=>V=n*Vm=1,739*22,4=38,956m3 H2