Question

se da a+b+c=800 ,a+b=5sipra 6 din [(a+b+c)-20 , b:a=1 rest c .Sa se afle nr

Answer 1

a+b+c=800
a+b=5/6 din(800-20)
a+b=5/6 din 780
a+b=780:6×5
a+b=130×5
a+b=650
a+b+c=800
650+c=800
c=800-650
c=150
b:a=1 rest 150
a+b=650
b) |_|+150
a) |_| }total 650
650-150=500 (2 segmente egale)
500:2=250 (1 segment )
b=250+150=400
a=250