Question

se dă a supra b= 0,(6). sa se calculeze 2a+3b supra 3b

Answer 1

a/b=6/9=2/3

$\frac{2a+3b}{3b} = \frac{2a}{3b} + \frac{3b}{3b} = \frac{2}{3} * \frac{2}{3} +1= \frac{4}{9} +1= \frac{4+9}{9} = \frac{13}{9}$