Question

se da
abcd-romb
ac-24 cm(diagonala)
bd-10 cm(diagonala)
perimetrul rombului?

Answer 1

$d_{1}^2 + d_{2}^2=2( a^{2} + b^{2} )$
$24^2+10^2=4a^2$
$4a^{2} =676$
$a^{2}=169$
$a=13$
P=$4a=4*13=52cm$