Question

Se da: BC=10; AC=8.
Se cere:AB; AM; AD; Aria, sin B, cos C, tg B

Answer 1

din teorema lui Pitagora => AB^2 = BC^2-AC^2 => AB ^2=100-64=36 => AB = radical din 36 = 6 
AM = inaltimea = (AC*AB)/BC = (8*6)/10 = 24/5
ARIA = A = (cateta1*cateta2)/2 = (AC*AB)/2 = (8*6)/2 = 24
sinB = AC/BC = 8/10=4/5
cosC = AC/BC=8/10=4/5
tgB= AC/AB=8/6=4/3