Question

se da egalitatea 7x[395-10x(8xa-62)]÷5=413 ajutor

Answer 1

7x[395-10x(8xa-62)]÷5=413
[ 395-10x(8xa-62)]÷5=413:7
[395-10x(8xa-62)]÷5=59
395-10x(8xa-62)=59×5
395-10x(8xa-62)=295
10x(8xa-62)=395-295
10x(8xa-62)=100
8×a-62=100:10
8×a-62=10
8×a=10+62
8×a=72
a=72:8
a=9

PROBA :

In loc de a pun 9 =>

7x[395-10x(8x9-62)]÷5=
=7×[395-10×(72-62):5=
=7×(395-10×10):5=
=7×(395-100):5=
=7×295:5=
=7×59=
=413 (adevarat )

Answer 2

7*[395-10*(8*a-62)]:5=413

7*[395-10*(8*a-62)]=413x5

7*[395-10*(8*a-62)]=2.065

395-10*(8a-62)=2065:7

395-10*(8*a-62)=295

10*(8*a-62)=395-295

10*(8xa-62)=100

8*a-62=100:10

8*a-62=10

8*a=62+10

8*a=72

a=72:8

a=9