Question

Se da:
Energia cinetica= 7,28 *10e-18J
raza = 1 * 10e-3 m
Masa electronului -9,1 *10e-31 kg
q0 = 1,60 *10e-19 C
Sa se afle inductia si acceleratia

Answer 1

[tex]\displaystyle Se~da:\\ \\ E_c=7,28\times 10^{-18}J\\ \\ r=10^{-3}m\\ \\ m=9,1\times 10^{-31}kg\\ \\ q_0=1,6\times 10^{-19}C\\ \\ B=?T\\ \\ a=?\frac{m}{s^2}\\ \\ \\ Formule:\\ \\ F_l=q_0\times v\times B\\ \\ B=\frac{F_l}{q_0\times v}\\ \\ \\[/tex]


$\displaystyle E_c=\frac{m\times v^2}{2}\\ \\ v=\sqrt\frac{2\times E_c}{m}\\ \\ \\ F_l=F_{cp}\\ \\ \\ F_l=\frac{m\times v^2}{r}\\ \\ F_l=\frac{m\times2\times E_c}{r\times m}\\ \\ F_l=\frac{2\times E_c}{r}\\ \\ \\ B=\frac{2\times E_c}{r\times q_0\times \sqrt\frac{2\times E_c}{m}}$


[tex]\displaystyle a=\frac{v^2}{r}\\ \\ a=\frac{2\times E_c}{m\times r}\\ \\ \\ Calcule:\\ \\ B=\frac{2\times 7,28\times 10^{-18}}{10^{-3}\times 1,6\times 10^{-19}\times \sqrt\frac{2\times 7,28\times 10^{-18}}{9,1\times 10^{-31}}}=0,02275T\\ \\ a=\frac{2\times 7,28\times 10^{-18}}{9,1\times 10^{-31}\times 10^{-3}}=1,6\times 10^{16}\frac m{s^2}[/tex]

P.s. Fl-Forta lui Lorentz; Fcp-Forta centripeta.