Question

Se da expresia
E(x) = (2x+ 3)^2−2(x+ 3)(x−1) + (3−x)(x+ 3)−44

Aratati ca E(1) · E(2) · E(3) ····· E(2020) = 0

Answer 1

Ai poza cu rezolvarea atasata

~orice numere inmultite cu 0, rezultatul va fi 0~

Answer 2

E(x)=(2x+3)^2-2(x+3)(x-1)+(3-x)(x+3)-44

E(1)=(2+3)^2-2(1+3)(1-1)+(3-1)(1+3)-44

E(1)=5^2-2×4×0+2×4-44

E(1)=25+8-44

E(1)=-11

E(2)=(2×2+3)^2-2(2+3)(2-1)+(3-2)(2+3)-44

E(2)=7^2-2×5×1+1×5-44

E(2)=49-10+5-44

E(2)=39+5-44

E(2)=44-44

E(2)=0

E(1)×E(2)×E(3)×...×E(2020)=0

-11×0×....×E(2020)=0

Explicatie: Orice numar inmultit cu 0 este egal cu 0.