Question

Se da functia f:R-->R,f(x)=x+3 calculati
f(2)+f(2la puterea2)+f(2 la p 3) +....+f(2 la p 7)

Answer 1

Răspuns:

f:R-->R,f(x)=x+3

f(2)= 2+3=5

f(2^2)=f(4)=4+3=7

f(2^3)=f(8)= 8+3=11

f(2^4)=f(16)= 16+3=19

f(2^5)=f(32)= 32+3=35

f(2^6)=f(64)= 64+3=67

f(2^7)=f(128)= 128+3= 131

f(2)+f(2^2)+f(2^3)+f(2^4)+f(2^5)+f(2^6) +f(2^7)=

5+7+11+19+35+67+131=

12+30+102+131=

42+233=

275

Explicație pas cu pas: