Question

Se da: m-1890g. Ro-2700kg/m^2. S-1,4mm^2. rezistorul- 2,8*10^-8 U=10V DE aflat I-intensitatea

Answer 1

Se da:
m=1890g=1,89kg
D=2700kg/m³
S=1,4mm²=1,4*10⁻⁶m²
p=2,8*10⁻⁸ohm*m
U=10V
I=?A

Formule:
[tex]I= \frac{U}{R}\\ R=p \frac{l}{S}\\ R= \frac{pV}{S}/S\\ R= \frac{pm}{D}/S^{2}\\ R= \frac{pm}{DS^{2}}\\ I=U/\frac{pm}{DS^{2}}\\ I= \frac{UDS^{2}}{pm}\\ Calcule:\\ I= \frac{10*2700*(1,4*10^{-6})^{2}}{2,8*10^{-8}*1,89}=1A [/tex]