Question

Se da nr A=2 la n+3 ×3 la n +2 la n+1 × 3 la n+1 +2 ×6 la n Aflati daca descompunerea factori primi a nr A este 2⁷ ×3³ afla nr n
ajtor dau coroana ​

Answer 1

Am atasat o rezolvare.

Answer 2

A = 2^(n+ 3)*3^n + 2^(n+1)*3^(n+1) +2*6^n = 2^n*2^3*3^n + 2^n*2*3^n*3 + 2*6^n = 8*6^n + 6*6^n + 2*6^n = 16*6^n = 2^4*2^n*3^n = 2^(n+4)*3^n

Dar A= 2^7*3^3 => n+4 = 7 si n=3