Question

Se dă nr n= | radical din1,8× 0,2(6)-radical din2,25×0,(3)|×(10radical din3)​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

$\it |\sqrt{1,8\cdot0,2(6)}-\sqrt{2,25\cdot0,(3)}|\cdot10\sqrt3=\Big|\sqrt{\dfrac{18}{10}\cdot\dfrac{24}{90}}-\sqrt{\dfrac{225}{100}\cdot\dfrac{3}{9}}\Big|\cdot10\sqrt3=\\ \\ \\ =\Big|\sqrt{\dfrac{3\cdot144}{900}}-\sqrt{\dfrac{225\cdot3}{900}}\Big|\cdot10\sqrt3=\Big|{\dfrac{12\sqrt3-15\sqrt3}{30}\Big|\cdot10\sqrt3 =\Big|{\dfrac{-3\sqrt3}{30}\Big|\cdot10\sqrt3=$

$\it =\dfrac{3\sqrt3}{30}\cdot\dfrac{10\sqrt3}{1}=\dfrac{30\cdot3}{30}=3$