Question

se dau cinci numere care respecta următoarele conditii a=b×3+4 b=c×2+3 c=d+21 e=d+1 a+b+c+d+e=376 sa se afle numerele

Answer 1

Se dau cinci numere care respecta următoarele conditii
 a=b×3+4=3b+4⇒                  a = 3b + 4
 b=c×2+3=2c+3⇒ b - 3=2c⇒c = (b - 3)/2
 c=d+21             (b-3)/2=d+21⇒b - 3 = 2d + 42⇒b -3 -42 = 2d⇒b - 45 =2d⇒
                                               d = (b - 45)/2
 e=d+1                             e=d+1=(b - 45)/2+ 1=(b-45+2)/2=(b-43)/2
                                                e = (b - 43)/2
a+b+c+d+e=376
(3b+4)+b+(b-3)/2+(b-45)/2+(b-43)/2=376
2(4b+4)+(b-3)+(b-45)+(b-43)=376×2
8b+8+b-3+b-45+b-43=752
11b=752+88-5
11b=835
b=835/11
a = 3b + 4=3×835/11+4=(3340+44)/11=3384/11
a=3384/11
c = (b - 3)/2=(835/11-3)/2
d=c-21=
e=d+1=