Question

Se dau n numere naturale.Afisati puterile lui 2 in c++.

Answer 1

#include <iostream.h>

#include <math.h>

int main()

{

int n, v[101], i, p;

cout<<"n="; cin>>n;

for(i=1;i<=n;i++){

 cout<<"v["<<i<<"]="; cin>>v[i];

}

for(i=1;i<=n;i++){

 p=0;

 while(pow(2,p)<=v[i]){

  if(pow(2,p)==v[i])

   cout<<v[i]<<' ';

  p++;}

}

}