Question

se dau nr 79 345,7672,4910,32805.a)ordoneaza crescator nr date;b)descompune nr pare in suma de mii,sute ,zeci,unitati;c)rotunjeste nr impare la zeci de mii​

Answer 1

a)4910,7672,32805,7934

b)7672 mii-7000+sute-600+zeci-70+unitati-2=7672

4910

mii-4000+sute-900+zeci-10=4910

c)79345-80000

32805-30000

Answer 2

Răspuns:

a) 4910, 7672, 32805, 79345.

b)79345=7+9+3+4+5, 7672=7+6+7+2, 4910=4+9+1+0, 32805=3+2+8+0+5.

c)79345=79000, 7672=8000, 4910=5000, 32805=33000.

Sper ca este bine si ca te-am ajutat!!!