Question

Se dau numerele : a=[1+(2+3*4)*5+4]:3-2*2=
b=(9+8-7)*6(7+8-9)=
c=44:(44:4)*4+4-(4+4*4)=
Calculeaza : c*(a-b)

Answer 1

a = [ 1 + ( 2 + 3 x 4 ) x 5 + 4 ] : 3 - 2 x2
a = [ 1 + ( 2 + 12 ) x 5 + 4 ] : 3 - 4
a = ( 1 + 14 x 5 + 4 ) : 3 - 4
a = ( 1 + 70 + 4 ) : 3 - 4
a = 75 : 3 - 4
a = 25 - 4
a = 21

b =( 9 + 8 - 7 ) x 6 ( 7 + 8 - 9 )
b = 10 x 6 x 6
b = 360

c = 44 : ( 44 : 4 ) x 4 + 4 - ( 4 + 4 x 4 )
c = 44 : 11 x 4 + 4 -( 4 + 16 )
c = 44 : 11 x 4 + 4 - 20
c = 4 x 4 + (-16)
c = 16 + (-16)
c = 0
c x (a - b) = 0 x ( 21 - 360) = 0
aceasta inmultire este o fara sa mai facem calculele
orice numar inmultit cu 0 este 0

Answer 2

*6(7+8    este bun cred ca ai sris c=gresit