Question

Se dau numerele a=100111 in baza 2 ,b=110101 in baza 2
si c=110111 in baza 2.Scrie numerele date in sistem zecimal si afla apoi ultima cifra a sumei a+b+c

Answer 1

a=100111₍₂₎ = 1*2⁵+1*2²+1*2¹+1*2⁰ = 32+4+2+1  = 39₍₁₀₎
b=110101₍₂₎ = 1*2⁵+1*2⁴+1*2²+1*2⁰ = 32+16+4+1= 53₍₁₀₎
c=110111₍₂₎  = 1*2⁵+1*2⁴+1*2²+1*2¹+1*2⁰ = 32+16+4+2+1 = 55₍₁₀₎

u(39 + 53 + 55) = u(9+3+5) = u(17) = 7 .