Question

Se dau numerele: a=2+3×(2+8)-9×0 b=2×4×5-4×9+2×1 c=3×4×2×10×0+2 Calculează: a-b×c= a-b+5×c= a-2×(b+c)=

Answer 1

a=2+3(2+8)-9*0
a=2+3*10-0
a=2+30-0
a=32

b=2*4*5-4*9+2*1
b=8*5-36+2
b=40-36+2
b=4+2
b=6

c=3*4*2*10*0+2
c=0+2
c=2

a-b*c=32-6*2=32-12=30

a-b+5*c=32-6+5*2=26+10=36

a-2(b+c)=32-2(6+2)=32-2*8=32-16=16

Answer 2

a=32
b=6
c=2
a-bxc=32-6x2=20
a-b+5xc=32-6+5x2=36
a-2x(b+c)=32-2x(6+2)=16