Question

Se dau numerele:a=2+3×(2+8)-9×0
b=2×4 ×5-4×9+2×1
c=3×4×2 ×10×0+2
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Answer 1

Răspuns:

a=2+3×(2+8)-9×0

a=2+3×10-0

a=2+30

a=32

b=2×4×5-4×9+2×1

b=8×5-36+2

b=40-36+2

b=6

c=3×4×2×10×0+2

c=0+2

c=2

a-b×c=32-6×2=32-12=20

a-b+5×c=32-6+5×2=32-6+10=26+10=36

a-2×(b+c)=32-2×(6+2)=32-2×8=32-16=16

sper că te-am ajutat!

Answer 2

Răspuns:

A= 2+3×(2+8)-9×0

A= 2+3×10-9×0

A=2+30-0

A=32-0

A=2

B=2×4×5-4×9+2×1

B=8×5-4×9+2

B=40-36+2

B=4+2

B=7

C=3×4×2×10×0+2

C= 12×2×0+2

C=24×0+2

C=0+2

C=2

toate punctele ! a,b,c

sper că te-am ajutata