Question

se dau numerele A=2 la puterea1996 inmultit cu 5 la puterea 1998 si B=2 la putere1998 inmultit cu 5 la puterea 1996 .sa se compare nr.cate zerouri are numarulA=B

Answer 1

Fie M=(2^1996 * 5^1996)

A=2^1996 * 5^1998=(2^1996 * 5^1996)(1*5^2)=25*(2^1996 * 5^1996)=25M

B=2^1998 * 5^1996=(2^1996 * 5^1996)(1*2^2)=4*(2^1996 * 5^1996)=4M

A>B