Question

se dau numerele:a=214 b=2 c=325 sa se afle a) a×b+c-b×[(a+b×c)-(a+c)]÷5= b) c+b×a+b×[(c-a)×b-a]=

Answer 1

a=214 b=2 c=325

a) a×b+c-b×[(a+b×c)-(a+c)]÷5=
214 x 2+325-2 x [(214+2 x 325)- (214+325)]:5=
428 +325-2 x [(214+2 x 325)- (214+325)]:5=
428 +325-2 x [(214+650)- (214+325)]:5=
428 +325-2 x [(214+650)- 539]:5=
428 +325-2 x (864- 539):5=
428 +325-2 x 325:5=
753-2 x 325:5=
753-650:5=
753-130= 623

b) c+b×a+b×[(c-a)×b-a]=
325 + 2 x 214 + 2 x [(325 - 214) x 2 - 214] =
325 +428+ 2 x (111 x 2 - 214) =
753+2 x 8 =
753+16 =769